heaven to me is flamin hot cheetos
was actually kinda terrible D:
Because it's f*cking hilarious. :D
Hey guys I'm Dayana and I'm reading ALL OF THIS and I am feeling much sympathy for the poor fellow who got a broken nose. Or am I?
didn't get the sweet satisfaction I was expecting.
It would be C if that 7x^2 wasn't there. But it's actually D since 7x^2 fits nicely into both of those polynomials.
16x^3 - 6x + 7/2 I left 7/2 as a term since it's exact. But yeah you're right. :]
24x^2y + 8xy^2 + 8xy ----------------------------- -4xy -6x - 2y - 2 Yep.
You need to divide the co-efficients. The variables with powers stay as they are. 21/-7 = 3 (plus a^3) = 3a^3 - 14/-7 = 2 (opposites cancel, add variables) = 2a
It's A .
Gotta go to one of the houses to get some agua. lul
The dryspell one = lmao
Yeah the Pokemon follow you. Pidgey looks lolicious when he/she follows you. Been playing the ROM and so far it's awesome.
I haven't used that method in a couple semesters so it's a bit foggy. I think I can still do it though if I tried hard enough. oh lulz
Oh, yes, I do. This would involve synthetic/long division I think. Going from a 3rd power to a 2nd power, or if it's a 5th power, down to a 4th power or lower. If the term (x+b) at the end is over 1, long division is required. If it's just 1 or 0, it can be synthetically simplified. Something like that?
Hmm I don't think so. Sounds familiar though?
(x^2 + 3x - 2)(x + 3) x^3 + 3x^2 + 3x^2 + 9x - 2x - 6 x^3 + 6x^2 + 7x - 6 yep.
Hey this is decent practice. And I'm bored.
2x(x-3)(x+2) This is a quadratic equation. you can tell due to the 2x in front, and the fact there is a (x+/-a)(x+/-b). First distribute 2x into the term (x-3). Which should give 2x^2-6x. Then distribute that polynomial into (x+2). Which should go like this (this might be messy since it's on a computer): 2x^2 - 6x(x+2) = 2x^3 + 4x^2 - 6x^2 - 12x This is a fairly long one, so you can combine the squared terms 4x^2 and -6x^2. (2x^3) - (2x^2) - 12x That should be your result. Although I haven't worked with these kinds of problems in a while so bare with me. lol
Ah I see. And yeah, it is true due to commutative property of addition kthx ;o EDIT: Also I'd probably ask KHV if I had trouble on a math problem. Although, really, I wouldn't expect a right answer. I'd just be looking for help mostly. lol
