When I'm integrating with spherical coordinates in the first octant

Discussion in 'The Spam Zone' started by Always Dance, Nov 14, 2011.

  1. Always Dance Chaser

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    Does theta range from 0 to pi/2 or 0 to pi/4? I thought the first octant translated to the first quadrant which would make it pi/2, but I'm getting the answer to this problem wrong and it looks like I'm supposed to be taking theta from 0 to pi/4...

    halp?
     
    Always Dance, Nov 14, 2011
    Always Dance, Nov 14, 2011
    #1

  2. Makaze Some kind of mercenary

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    Show us the problem?
     
    Makaze, Nov 14, 2011
    Makaze, Nov 14, 2011
    #2

  3. Krowley Moderator

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    Try (pi/2)(pi/2)
    Of course I don't know a lot about Integrals in spherical coordinates
     
    Krowley, Nov 14, 2011
    Krowley, Nov 14, 2011
    #3

  4. Always Dance Chaser

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    Use spherical coordinates to find ∫∫∫z DV where Q lies between the spheres x^2+y^2+z^2=1 and x^2+y^2+z^2=4 in the first octant.

    Wolfram is telling me that I'm setting the integral up right so I guess I'm just screwing up solving it somewhere. I cannot figure out where >_>

    [​IMG]
    Halp? I'm supposed to get 15pi/16
     
    Always Dance, Nov 14, 2011
    Always Dance, Nov 14, 2011
    #4

  5. Makaze Some kind of mercenary

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    No can do, I have not studied this (yet). But now someone else can. Cheers...
     
    Makaze, Nov 14, 2011
    Makaze, Nov 14, 2011
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  6. Always Dance Chaser

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    Pray you never have to. Calc III sucks so much ass.
     
    Always Dance, Nov 14, 2011
    Always Dance, Nov 14, 2011
    #6
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